Joint Entrance Examination/AIEEE 2009/Q077 KINEMATICS

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Original Question by

Here's the question...

Q77. A particle has an initial velocity of 3iˆ+4jˆ and an acceleration of 0.4iˆ+ 0.3jˆ. Its speed after 10 s is

  • (1) 7 2 units
  • (2) 7 units
  • (3) 8.5 units
  • (4) 10 units

Posted by 05:48, 24 September 2009 (UTC)

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Reply to the thread, posted by

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Additional notes

SOLUTION:[1] v=u+at =(3iˆ+4jˆ)+10(0.4iˆ+0.3jˆ) =(3iˆ+4jˆ)+(4iˆ+3jˆ) =7iˆ+7jˆ

These comments, along with the notes on the left, were contributed by 05:54, 24 September 2009 (UTC)