Joint Entrance Examination/AIEEE 2009/Q070 VERNIER CALLIPER

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Original Question by

Here's the question...

q70. In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (= 0.5°), then the least count of the instrument is

  • (1) Half minute
  • (2) One degree
  • (3) Half degree
  • (4) One minute

Posted by 04:58, 24 September 2009 (UTC)

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Reply to the thread, posted by

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Additional notes

29 Div of M.S = 30 Div of V.S 1 Div of V.S = 29/ 30 Div of M.S Least count = 1 Div of M.S – 1 Div V.S = 1/ 30 Div. of M.S = 1/30 *1/2=1/60°=1minute

These comments, along with the notes on the left, were contributed by 05:02, 24 September 2009 (UTC)