Joint Entrance Examination/AIEEE 2009/Q014 calculus


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Original Question by 164.100.170.4

Here's the question...

Given P(x)=x4+ax3+bx2+cx+d such that x=0 is the only real root of P'(x)=0 . If P(-1)<P(1) , then in the interval [-1,1],

  • (1)P(-1) neither is the minimum nor P(1) is the maximum of P
  • (2) P(-1) is the minimum and P(1) is the maximum of P
  • (3) P(-1) is not minimum but P(1) is the maximum of P
  • (4) P(-1) is the minimum but P(1) is not the maximum of P

Posted by 164.100.170.4 05:42, 27 September 2009 (UTC)

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Reply to the thread, posted by 164.100.170.4

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Additional notes

ans:[3] P(x)=x4+ax3+bx2+cx+d Now P'(0)= 0 => c=0. =>P(x)= P(x)=x4+ax3+bx2+d clearly we see that P(1) is maximum but P(-1) is not minimum.

Clearly is maximum but is not minimum. Correct choice: (3)

These comments, along with the notes on the left, were contributed by 164.100.170.4 05:48, 27 September 2009 (UTC)