Electric Circuit Analysis/Simple Resistive Circuits
ELECTRIC CIRCUITS ANALYSIS COURSE 
Lesson Review: Lesson 1The first lesson was about passive sign convention. The lesson introduced circuit components which will be encountered in electric circuit analysis.
Lesson PreviewThis lesson is about simple resistive circuits. The student is expected to have understood the following at the end of the lesson:


Part 1Voltage SourceThis is possibly the simplest circuit. The voltage source supplies a voltage to the circuit. When this voltage is applied over a resistor, R, there is a current. Equation 2.1
This equation explains the relation between all three elements in the circuit. In this case the voltage source has the same magnitude as the voltage drop across the resistor. We know that it is V. The resistor has a certain amount of Ohms depending on its rating. We now know R. With algebra I = V/R. So as long as you know two of the variables then you can find the third. Now comes the power part of the circuit analysis. Equation 2.2
Once Equation 2.1 is solved then this equation should follow quickly. The I and V are the same variables so insert them into the equation and solve for P (Watts). With these two equations, 1.1 and 1.2, and a little bit of algebra you get: Equation 2.3
Equation 2.4

Part 2As an explanation, the power running through is the voltage times the current. This is instantaneous power rather than power used over time. Power has to be supplied and consumed. In a perfect world without heatloss both are equal. The source supplies the required power that is consumed in this case by the resistor. Example 2.1Given': Find: I, the current in Amps. The power produced by the source. The power consumed by the resistor. Solution: Using the equations:

Part 3Current SourceAll that will happen here is that the givens will change. Rather than knowing what the voltage is across the resistor we now know what the current is flowing through the resistor.

Part 4Example: 2.1Given': Find: V, the voltage. The power produced by the source. The power consumed by the resistor. Solution: Using the equations:
Of course, power consumed equals power supplied in this perfect universe, which is only found in this course. 
Part 5: More ExamplesExample 2.2Given': Find: I, the current in Amps. The power produced by the source. The power consumed by the resistor.

Part 6Example 2.3Given': Find: V, the voltage. The power produced by the source. The power consumed by the resistor.

Part 7Example 2.4Given': Find: V, the voltage. R, the resistance

Part 8Example 2.5Given': Find: I, the current in Amps. R, the resistance.

Part 9Example 2.6Given': Find: V, the voltage. I, the current.

Part 10: Exercise 2
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