1 A line of charge density λ situated on the y axis extends from y = -3 to y = 2. What is the y component of the electric field at the point (3, 7)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where B={\displaystyle {\mathcal {B}}=}
2 A line of charge density λ situated on the y axis extends from y = -3 to y = 2. What is the y component of the electric field at the point (3, 7)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}
3 A line of charge density λ situated on the y axis extends from y = -3 to y = 2. What is the y component of the electric field at the point (3, 7)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, whereF={\displaystyle {\mathcal {F}}=}
4 A line of charge density λ situated on the y axis extends from y = 2 to y = 7. What is the y component of the electric field at the point (2, 9)? Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
5 A line of charge density λ situated on the y axis extends from y = 2 to y = 7. What is the y component of the electric field at the point (2, 9)? Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where D2+E2={\displaystyle {\mathcal {D}}^{2}+{\mathcal {E}}^{2}=}:
6 A line of charge density λ situated on the x axis extends from x = 4 to x = 8. What is the y component of the electric field at the point (8, 4)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where A={\displaystyle {\mathcal {A}}=}:
7 A line of charge density λ situated on the x axis extends from x = 4 to x = 8. What is the y component of the electric field at the point (8, 4)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
8 A line of charge density λ situated on the x axis extends from x = 4 to x = 8. What is the x component of the electric field at the point (8, 4)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
9 A line of charge density λ situated on the y axis extends from y = 4 to y = 6. What is the x component of the electric field at the point (5, 1)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
10 A line of charge density λ situated on the y axis extends from y = 4 to y = 6. What is the y component of the electric field at the point (5, 1)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
11 A line of charge density λ situated on the y axis extends from y = 4 to y = 6. What is the y component of the electric field at the point (5, 1)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where F={\displaystyle {\mathcal {F}}=}:
12 A line of charge density λ situated on the x axis extends from x = 3 to x = 7. What is the x component of the electric field at the point (7, 8)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where C={\displaystyle {\mathcal {C}}=}:
13 A line of charge density λ situated on the x axis extends from x = 3 to x = 7. What is the x component of the electric field at the point (7, 8)?Answer{\displaystyle Answer} (assuming B>A{\displaystyle {\mathcal {B}}>{\mathcal {A}}}) is:14πϵ0∫ABCλds[D2+E2]F{\displaystyle is:{\frac {1}{4\pi \epsilon _{0}}}\int _{\mathcal {A}}^{\mathcal {B}}{\frac {{\mathcal {C}}\;\lambda ds}{\left[{\mathcal {D}}^{2}+{\mathcal {E}}^{2}\right]^{\mathcal {F}}\;}}}, where D2+E2={\displaystyle {\mathcal {D}}^{2}+{\mathcal {E}}^{2}=}: