Joint Entrance Examination/AIEEE 2009/Q076 WAVE OPTICS


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Original Question by 164.100.170.4

Here's the question...

Q76. A mixture of light, consisting of wavelength 590 nm and an unknown wavelength, illuminates Young’s double slit and gives rise to two overlapping interference patterns on the screen. The central maximum of both lights coincide. Further, it is observed that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is

  • (1) 885.0 nm
  • (2) 442.5 nm
  • (3) 776.8 nm
  • (4) 393.4 nm

Posted by 164.100.170.4 05:36, 24 September 2009 (UTC)

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Reply to the thread, posted by 164.100.170.4

Thread post

Additional notes

SOLUTION:[2] As 4th bright fringe of unknown wavelength coincides with 3rd bright fringe of known wavelength ⇒ 4Dλ/d = 3(590nm)D/d ⇒ λ= 3*590/4= 442.5 nm

These comments, along with the notes on the left, were contributed by 164.100.170.4 05:40, 24 September 2009 (UTC)