Vector space/Projection/Introduction/Section

For a direct sum decomposition of a -vector space , the linear mapping

is called the first projection (or projection onto with respect to the given decomposition or projection onto along ) and, accordingly,

the second projection of this decomposition. Since and are linear subspaces of , it is reasonable to call the composed mapping

a projection as well. Then we have a projection in the sense of the following definition.


Let be a field, a -vector space and a linear subspace. A linear mapping

is called a projection of onto , if and

holds.


Let be a finite-dimensional -vector space and , , a basis of . For a subset , set

the linear subspace corresponding to . Moreover, let

the corresponding projection. The image of this projection is . On , this mapping is the identity, one can also consider this mapping as

The kernel of this mapping is


For , equipped with the standard basis, we consider subsets with two elements and the corresponding projections (in the sense of example) onto the coordinate planes. The projections are

The images of some object in under these projections carry names like ground view etc.

For a subset with one element, the projections map to an axis.

A more abstract definition is the following which does not refer to a linear subspace.


Let be a field and a -vector space. A linear mapping

is called a projection, if

holds.

The identity and the zero mapping are projections.


Let be a field and a -vector space. For a direct sum decomposition

the projection onto is a projection in the sense of Definition. Such a projection

gives a decomposition

and is the projection onto .

Let be the projection onto . Write with . Then we have

and hence

Suppose now that

is an endomorphism with

Let . Then there exists some such that

Then

This means that the intersection of these linear subspaces is the zero space. For an arbitrary , we write

Here, the first summand belongs to the image and, because of

the second summand belongs to the kernel. Therefore, we have a direct sum decomposition.