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Upper triangular matrix/4x4/Kernel one-dimensional/Exercise
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Determine, for the real matrix
M
=
(
3
5
2
4
0
3
6
−
1
0
0
3
2
0
0
0
3
)
,
{\displaystyle {}M={\begin{pmatrix}3&5&2&4\\0&3&6&-1\\0&0&3&2\\0&0&0&3\end{pmatrix}}\,,}
its
Jordan normal form
(we do not ask for a basis).
Create a solution