Surreal number/Why isn't half-omega the (left) child of omega?

Surreal number/Why isn't half-omega the (left) child of omega? Click this link to see an answer given by Gemini, on 9 October 2024. This use of a chatbot raises two questions:

  1. Is the answer correct? (Answer: I don't know)
  2. Is it it appropriate to post something that might not be true on Wikiversity? (Answer: Yes! This is a lesson, not the Wikipedia article.)
Dali want's to know why omega's children follow the pattern of 0, while virtually all surreal parents follow the pattern used by 1, 2, 3...

This page should be viewed as the following student assignment:

  • Is Gemini's answer correct? If so, please elaborate. If not, either produce a better answer, or explain why Gemini is wrong.

Question: On the left (negative) side of the tree starting at , why did Conway choose to assign to that branch instead of ?

Answer follows

edit

That's a great question!

Conway's choice to assign ω-1 to the left branch of ω instead of ω/2 is based on the fundamental principles of surreal number construction.

Here's the reasoning:

  1. Recursive Definition: Surreal numbers are constructed recursively, meaning they are defined in terms of previously constructed numbers.
  2. Left and Right Sets: Each surreal number is defined by two sets: a left set (L) and a right set (R).
  3. Ordering: The ordering of surreal numbers is determined by the relative positions of their left and right sets. If every element of L is less than every element of R, then the number is well-defined.

Now, let's consider ω. It is defined as follows:

  • Left set: {0, 1, 2, 3, ...}
  • Right set: {}

When constructing the left branch of ω, we need to find a surreal number that is less than every element in the left set. ω-1 satisfies this condition because it is less than every natural number.

Why not ω/2? While ω/2 is indeed less than every natural number, it's not a well-defined surreal number at this point. To define ω/2, we would need to construct its left and right sets, which would involve introducing new surreal numbers.

Therefore, Conway chose ω-1 for the left branch of ω because it is a well-defined surreal number that fits the recursive construction rules and maintains the correct ordering.