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Riemann integral/1 over sqrt(x) of 0 to 1/Lower integral exists, no upper integral/Exercise
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Prove that for the function
]
0
,
1
]
⟶
R
,
x
⟼
1
x
,
{\displaystyle ]0,1]\longrightarrow \mathbb {R} ,x\longmapsto {\frac {1}{\sqrt {x}}},}
the lower integral exists, but the upper integral does not exist.
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