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Propositional logic/Universally valid/1/Exercise
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Show that the propositional expression
(
r
→
(
p
∧
¬
q
)
)
→
(
¬
p
→
(
¬
r
∨
q
)
)
{\displaystyle {\left(r\rightarrow {\left(p\wedge \neg q\right)}\right)}\rightarrow {\left(\neg p\rightarrow {\left(\neg r\vee q\right)}\right)}}
is always valid.
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