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Logarithm/Integration of hyperbola/Function equation/Exercise
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Prove the relationship
∫
1
a
b
1
x
d
x
=
∫
1
a
1
x
d
x
+
∫
1
b
1
x
d
x
{\displaystyle {}\int _{1}^{ab}{\frac {1}{x}}dx=\int _{1}^{a}{\frac {1}{x}}dx+\int _{1}^{b}{\frac {1}{x}}dx\,}
for
a
,
b
∈
R
+
{\displaystyle {}a,b\in \mathbb {R} _{+}}
,
only using rules for integration.
Create a solution