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Location-independent initial value problem/y is t^3 over t^2+1/y (1) is 2/Exercise
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Solve the initial value problem
y
′
=
t
3
t
2
+
1
with
y
(
1
)
=
2
{\displaystyle y'={\frac {t^{3}}{t^{2}+1}}{\text{ with }}y(1)=2}
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