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Linear system/Substitution method/2/Exercise
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Solve the linear system
5
y
−
z
+
7
=
6
3
y
+
6
z
+
3
=
−
2
8
y
+
8
z
+
7
=
3
{\displaystyle {\begin{matrix}5y&\,\,\,\,-z&+7&=&6\\3y&+6z&+3&=&-2\\8y&+8z&+7&=&3\,\end{matrix}}}
with the
substitution method
.
Create a solution