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Linear mapping/Basis/(1,3) to 5 and (2,-3) to (4)/(7,6)/Exercise
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Consider the linear map
φ
:
R
2
⟶
R
{\displaystyle \varphi \colon \mathbb {R} ^{2}\longrightarrow \mathbb {R} }
such that
φ
(
1
3
)
=
5
and
φ
(
2
−
3
)
=
4.
{\displaystyle \varphi {\begin{pmatrix}1\\3\end{pmatrix}}=5{\text{ and }}\varphi {\begin{pmatrix}2\\-3\end{pmatrix}}=4.}
Compute
φ
(
7
6
)
.
{\displaystyle \varphi {\begin{pmatrix}7\\6\end{pmatrix}}.}
Create a solution