Introduction to Programming/Answers to the exercises
Checking An Error Condition
editIn programming there is rarely one right answer, but for something this simple, your answer should look something like this:
if (divisor != 0) { quotient = dividend / divisor; } else { ReportErrorMessage; }
Fibonacci Numbers
editint fN = 0; int fNplus1 = 1; int counter = 0; while (counter < 11) { fNplus2 = fN + fNplus1; print fN; fN = fNplus1; fNplus1 = fNplus2; counter += 1; }
A variation, in Perl:
my $counter = 0; my $F = 1; my $prev_F = 0; while( $counter < 10 ) { print $F . "\n"; my $x = $F; $F = $prev_F + $F; $prev_F = $x; $counter++; }
Python 3 version :
f = 1 prevF = 0 counter = 0 while counter < 10: #While loop. What's underneath it runs until counter becomes (counter < 10). counter += 1 #You can write this line also as "counter = counter + 1". It assigns 'counter' variable to itself increased by one. print(prevF) prevF += f counter += 1 #We add one to 'counter' variable before each character is printed on screen. print(f) f += prevF