How things work college course/Momentum transfer under elastic and inelastic collisions
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Wikipedia and other pages edit
Experimental results edit
All experiments involved a compound pendulum made from pine. The inverted pendulum was a "knockdown" experiment in which the critical path length for knockdown was obtained. We measured path length because it was easiest to measure. The potential energy associated with the path length is Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "http://localhost:6011/en.wikiversity.org/v1/":): {\displaystyle mg\ell\sin\alpha} where is the angle of inclination. Most experiments involved finding the sad/happy pathlength ratio. The simplest theory says that happy is fully elastic and sad is fully inelastice, and the sad/happy pathlength ratio is 4.
Preliminary Results (inverted) edit
Since a happy ball delivers twice the momentum as a sad one, it stands to reason that the sad ball needs to go twice as fast to knock down the block. But recall that by energy conservation, the speed of a ball sliding down a ramp varies as the squareroot of the height. At a 12 degree ramp we found that the happy ball pathlength was 43 cm while the sad path length was 80.5 cm. The sad/happy pathlength ratio was 80.5/43=1.87
Steeper ramp (first run) edit
Here we performed experiments on the inverted pendulum (knockdown) and a stable pendulum (in which amplitude was measured).
Inverted (knockdown) mode edit
We changed the ramp slope 21.3 degrees. The paths were 62.5 and 139.5 cm long, respectively for happy and sad. The sad/happy pathlength ratio was 139.5/62.5=2.23 The block was pine with height 14, thickness 4, width 7 cm. The mass of the block was block 174.4 gm. The path length (continued straight) from the ramp's edge to the block was 2.6 cm. The bottom of the ramp is 7.2 cm above the bottom of the block.
Balanced block on its side so that almost 50% was over and edge and measured bounce of happy. It fell down 26 cm and came back up 8.5 cm. On the table the happy fell down 100 cm and came back up 87.5 cm.
 Ball mass and diameter: happy 9.0 gm, sad 9.8 gm, diameter 2.44 cm.
 The block was almost touching the ramp and warped so that the wall was perpendicular to the sloped ramp.
 This was the last experiment that did not use the 2meter sticks to center the ball on the ramp.(20 November 2014)
Stable (amplitude measurement)mode edit
Thursday 21 November 2014:
 Two 2meter rulers were place on the track. This lifted the ball up and also centered it as it rolled along the ramp. The 2meter rulers had a thickness of .6 cm and created a groove that was 0.6 cm wide. We estimate that the ball struck the block between .5 cm and 1 cm from the bottom of the block.
 Push pins were inserted about 0.1 cm below the top of the block and the block was supported so it's bottom was 12.3 cm above the table. The distance to between the block and the ramp was 2.2 cm, as measured by placing a ruler along the top of a 2meter ruler that was used to align the rolling balls. A pendulum amplitude 2.05 cm was achieved with both happy and sad. This amplitude was measured at the bottom of the block (from equilibrium). The top of the 2meter ruler was 11.25 cm above the table at it's lowest point.
 The happy and sad paths as measured by the 2meter rulers was 25 cm and 70 cm, respectively. Sad/happy pathlengh ratio = 70/25 = 2.8.
Steeper ramp (second run) edit
We moved the table and repeated the previous experiment, making some improvements in the design:
 Clamps were placed on the two meter sticks, permitting the ramp to be extended farther.
 In knockdown mode (inverted pendulum), we used a heavy metal plate to align the block so that it was always in the same place.
 In stable (compound pendulum) mode, we used tape to assure that the pendulum was always at the same location.
Knockdown mode edit
Sad/happy pathlength ratio = 169cm/83cm=2.04
Stable mode edit
Sad/happy pathlength ratio = 112cm/57cm=1.965
Third run (w/Teaching Assistant) edit
stable mode edit
 Sad/happy pathlengs = (140+1)cm/(70+1)cm = 1.985^{[2]}
 Amplitude = 3cm/13.5cm = .2222 radian
knockdown edit
 Sad/happy ratio 205+2cm/80+2cm=2.52 ([the 205 was estimated because we could not exceed 200)
The ball struck roughly 2 cm below the top.
Matlab:compound pendulum with elastic/inelastic collisions edit
Linear and angular momentum transfer equations edit
For a nonspinning ball and a simple pendulum with an inelastic collision, the formula is a simple matter of momentum conservation, mv_{0} = (m+M) v_{1}, where m, M, v_{0}, v_{1} are the mass of the bullet, pendulum, speed of bullet and final speed, respectively. For a spinning ball that does not embed itself into the pendulum, the situation is somewhat different from the traditional ballistic pendulum because the ball can roll along the pendulum after the initial collision.
The figure to the right shows an inelastic collision between a spinning ball and a compound pendulum. The spinning (solid) ball has mass, , and radius . The ball's initial angular and linear speeds are, and , and the corresponding final state of the ball is , and . The ball strikes the block at a point from the axis or rotation, and is the pendulum's moment of inertia. The pendulum's initial angle is , and it acquires and angular velocity of immediately after the collision with the ball.
To visualize this situation it is helpful to imagine that a spring mechanism quickly brings the ball at rest with respect to the pendulum. Here, "at rest" means that the ball and pendulum have no relative motion at the point of contact between them. The ball's center of mass might be moving if the ball is rolling. If the collision is completely inelastic, the spring mechanisms will compress, perhaps like ideal springs, but they do not decompress once the springs have come to rest. This model is somewhat "uncomfortable" because there are actually two spring mechanisms, for vertical and horizontal motion. Only if both mechanisms are carefully balanced will both springs come to maximum compression at the same time. If this is a wellposed physical problem (i.e., with a unique solution), this assumption that both springs come to rest simultaneously is not necessary. We shall speak no more of this blemish in the derivation.
During the time it takes the springs to compress, both the ball and pendulum will change their velocities. But we assume that the impulse time is so short that neither moves an appreciable distance during this first phase of the collision. (The second phase consists of the ball rolling along the block as it exerts a normal force and hence further torque on the pendulum.)
Four equations in four variables edit
Once we place the ball on the ramp, it is not difficult to calculate the how the ball is moving (i.e. angular and linear velocity) just before it strikes the block. But the rest is rather complicated as we now have four variables to deduce, . This requires at least four equations and quite a bit of algebra is involved. Two involve the fact that the ball rolls along a moving pendulum:
 and
Another constraint is conservation of total angular momentum about the axis about which the pendulum rotates.
This discussion is getting to complicated for "How things work". For a really long calculation see:
Doing the algebra edit
click to see MatLab mfile for Sad and Stable)


%Third run (w/Teaching Assistant) Sad stable pendulum clc, close all, clear all M=.1744;% kg (kilograms) is mass of block mSad=.0098% kg mass of sad L=.14;% m (meters) is length of block pathSad= 1.40;%m is the distance the sad ball rolled down the ramp incline=21.3*pi/180;%degrees; is the incline angle in RADIAMS ghSad=9.81*pathSad*sin(incline);%initial potential energy of sad Iapprox=sqrt(M*L^2/3) %kg m^2 is the approximate moment of inertial (thin rod model) vSad=sqrt(ghSad*10/7)*cos(incline) thetaDot = mSad*vSad*L/Iapprox thetaMax = sqrt(2*Iapprox/9.81/M/L) thetaObserved = .222 BigOverSmall=thetaMax/thetaObserved 
Two student spinoff labs that need to be written edit
The period of a compound pendulum edit
This lab could be done at home or in as simply equipped classroom. All you need is two sewing pins and a block of wood such as a 2x4 (inch) board that is about 6 inches long.
In the approximation that the block is a thin rod of length L the period is the same as for a simple pendulum of 2/3 its length^{[3]}:
How fast do objects roll downhill? edit
It would be nice to perform this lab with an actual ramp and two different objects that roll (they need not have the same dimensions or mass). But you can use the photofinish image to do this at home without equipment. In the space below, use the animated gif on the left and the photofinish on the right to write a lab that students can do at home.
The theory is explained in various places on the internet. For example,ir we neglect wind drag and rolling resistance the speed of a rolling solid sphere is:^{[4]}
 , where is this distance rolled along the ramp and is the plane's inclination.
Images, references and footnotes edit
Images on Wikimedia Commons edit
References and footnotes edit
 One dimensional elastic and inelastic collisions by Richard Fitzpatrick at the University of Texas at Austin.
 Realworld Physics: Bouncingball
 Articles by Rod Cross (See also PHYSICS OF BOUNCE)
 Footnotes:
 ↑ See Jacobsen v. Katzer
 ↑ note that the pin was .5cm from the edge of the 14cm block
 ↑ https://en.wikipedia.org/w/index.php?title=Pendulum&oldid=632567803#Compound_pendulum
 ↑ http://www.physics.ohiostate.edu/~gan/teaching/spring99/C12.pdf