Return Boundary Value Problems
ut−α2∇2u=F{\displaystyle \scriptstyle u_{t}-\alpha ^{2}\nabla ^{2}u=F}
∇2u=F{\displaystyle \scriptstyle \nabla ^{2}u=F}
utt−c2∇2u=F{\displaystyle \scriptstyle u_{tt}-c^{2}\nabla ^{2}u=F}
div(E)=4πρ{\displaystyle div(E)=4\pi \rho }
curl(E)+1c∂B∂t=0{\displaystyle \scriptstyle curl(E)+{\frac {1}{c}}{\frac {\partial B}{\partial t}}=0}
curl(B)−1c∂E∂t=4πcJ{\displaystyle \scriptstyle curl(B)-{\frac {1}{c}}{\frac {\partial E}{\partial t}}={\frac {4\pi }{c}}J}
div(B)=0{\displaystyle \scriptstyle div(B)=0}